[LLVMdev] c const
baldrick at free.fr
Wed Aug 22 17:48:32 CDT 2007
> If A and B are function arguments then there is no "based on"
> relationship between pointer expressions A+0 and B+0. This is because
> changing one of the pointers, A for example, to point to a copy of
> the object it points to would change the value of the pointer
> expression A+0, but not the expression B+0.
I was assuming that *(A+0) and *(B+0) are pointer expressions. Is
that not the case?
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